Question

Two stones, having masses in the ratio of 3 : 2, are
dropped from the heights in the ratio of 4 : 9. The
ratio of magnitudes of their linear momenta just
before reaching the ground is (neglect air resistance)

Answer 1

v²=u²+2as here in both case u will be zero

momentum(p)=velocity × mass

here we need v

v=√2as (a=g=10m/s²)

in first case v = √2×10×4 =4√5

p = 4√5 × 3

= 12√5

in case 2

v=√2×10×9

= 6√5

p= 6√5 × 2

=12√5

HENCE RATIO IS 1:1