Magnetic Field Due to a Straight Current Carrying Conductor
Two straight ...
Question
Two straight long conductors AOB and COD are perpendicular to each other and carry currents i1 and i2. The magnitude of the magnetic induction at a point P at a distance 'a' from the point O in a direction perpendicular to the plane ACBD is
A
μ02πa(i1+i2)
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B
μ02πa(i1−i2)
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C
μ02πa(i21+i22)12
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D
μ02πai1i2(i1+i2)
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Solution
The correct option is Cμ02πa(i21+i22)12
The magnetic induction at the point P due to AOB and COD is along perpendicular directions hence the magnitude At P:Bnet=√B21+B22 =√(μ04π2i1a)2+(μ04π2i2a)2 =μ02πa(i21+i22)12