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Question

Two stretched strings have lengths l and 2l while tensions are T and 4T respectively: If they are made of same material the ratio of their frequencies is

A
2:1
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B
1:2
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C
1:1
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D
1:4
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Solution

The correct option is C 1:1
Frequency, ν=12lTμ where μ is mass per unit length
νTL
Thus, ν1ν2=T1L1.L2T2

We get ν1ν2=Tl.2l4T=1
ν1:ν2=1:1

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