Two strings are tied 2m apart on a rod and on the other end a mass 200 g is tied as shown in figure. Each string is 1.25m long. FInd the tensions T1 and T2 if the rod is rotated with 60rpm. Consider π2=10
A
6N,3N
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B
6.25N,3.75N
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C
4.25N,5.75N
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D
5.25N,4.75N
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Solution
The correct option is B6.25N,3.75N
From triangle sinθ=11.25=0.8⇒cosθ=0.6
Given ω=60rpm=2πrad/s
Resolve T1 and T2. T1cosθ+T2cosθ=mrω2 T1sinθ=T2sinθ+mg (T1+T2)(0.6)=0.2×(34)(2π)2 T1+T2=10 T1−T2=mgsinθ=0.2×100.8=2.5
solving T1=6.25N and T2=3.75N