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Question

Two strings are tied 2 m apart on a rod and on the other end a mass 200 g is tied as shown in figure. Each string is 1.25 m long. FInd the tensions T1 and T2 if the rod is rotated with 60 rpm. Consider π2=10

A
6 N,3 N
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B
6.25 N,3.75 N
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C
4.25 N,5.75 N
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D
5.25 N,4.75 N
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Solution

The correct option is B 6.25 N,3.75 N
From triangle sinθ=11.25=0.8cosθ=0.6
Given ω=60rpm=2π rad/s
Resolve T1 and T2.
T1cosθ+T2cosθ=mrω2
T1sinθ=T2sinθ+mg
(T1+T2)(0.6)=0.2×(34)(2π)2
T1+T2=10
T1T2=mgsinθ=0.2×100.8=2.5
solving T1=6.25 N and T2=3.75 N

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