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Question

Two strings ‘x’ and ‘y’ on a Veena playing the same note are slightly out of tune and produce 6 beats per second. The tension in ‘x’ is slightly decreased and it is found that the beats fall to 3 per second. If the original frequency of ‘x’ is 324 Hz, the frequency of ‘y’ is

A
318 Hz
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B
330 Hz
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C
518 Hz
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D
618 Hz
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Solution

The correct option is A 318 Hz
fx=324
As tension in x is decreased frequency of x decreases and as beats fall with decrease in frequency of x.
So, frequency of x is greater than frequency of y.
Beats=δxδy
6=324δy
δy=318 Hz

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