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Question

Two students appeared at an examination full stop one of them scored 5 marks more than the other and his marks was 56% of the dum of their marks.the marks obtained by them are-

1)39,30

2)41,32

3)42,33

4)43,34

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Solution

The question has mistake. Difference between their marks is 5 but given options have difference of something else. Though I have solved it, you can look at the method.

Solution:

Let the score obtained by other student be x.
and the first be x+5.
Sum of their marks=x+x+5=2x+5.
Marks of first student=56% of sum.
x+5 = 56/100(2x+5)
100(x+5) = 56(2x+5)
100x+500=112x+280
500-280=112x-100x
220=12x
x=55/3
score obtained by other student = 55/3
and score obtained by other student = x+5 = 55/3 + 5 = 70/3

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