Two students appeared at an examination full stop one of them scored 5 marks more than the other and his marks was 56% of the dum of their marks.the marks obtained by them are-
1)39,30
2)41,32
3)42,33
4)43,34
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Solution
The question has mistake. Difference between their marks is 5 but given options have difference of something else. Though I have solved it, you can look at the method.
Solution:
Let the score obtained by other student be x. and the first be x+5. Sum of their marks=x+x+5=2x+5. Marks of first student=56% of sum. x+5 = 56/100(2x+5) 100(x+5) = 56(2x+5) 100x+500=112x+280 500-280=112x-100x 220=12x x=55/3 score obtained by other student = 55/3 and score obtained by other student = x+5 = 55/3 + 5 = 70/3