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Second Order Reaction

Two substance...

Question

Two substances $A (_{1 / 2} = 5 m i n s)$ and B $t_{1 / 2} = 15 m i n s)$ follow first order kinetics are taken in such a way that initially [A]=4 [B]. Calculate the time after which the concentration of both the substance will be equal.

15 min

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20 min

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24 min

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30 min

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Solution

The correct option is A 15 min
After 15 min,
[A] = 0.5 after 3 half time and
[B] = 0.5 after one half time.

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Similar questions

A

(t_{1 / 2} = 5 m i n s)

B

(t_{1 / 2} = 15 m i n s)

[A] = 4 [B]

(t_{\frac{1}{2}} =

(t_{\frac{1}{2}} =

[A] = 4 [B]

A (t_{\frac{1}{2}} = 5 min)

B (t_{\frac{1}{2}} = 15 min)

[A] = 4 [B]

A (t_{\frac{1}{2}} = 5 min)

B (t_{\frac{1}{2}} = 15 min)

[A] = 4 [B]

[A_{0}] = 4 [B_{0}]

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