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Second Order Reaction

Two substance...

Question

Two substances, $A$ $(t_{1 / 2} = 5 m i n s)$ and $B$ $(t_{1 / 2} = 15 m i n s)$ following first-order kinetics are taken in such a way that initially $[A] = 4 [B]$ . Calculate the time after which the concentration of both the substances will be equal.

7.5 m i n

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15 m i n

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30 m i n

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10 m i n

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Solution

The correct option is B $15 m i n$

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Similar questions

A (_{1 / 2} = 5 m i n s)

t_{1 / 2} = 15 m i n s)

A (t_{\frac{1}{2}} = 5 min)

B (t_{\frac{1}{2}} = 15 min)

[A] = 4 [B]

(t_{\frac{1}{2}} =

(t_{\frac{1}{2}} =

[A] = 4 [B]

A (t_{\frac{1}{2}} = 5 min)

B (t_{\frac{1}{2}} = 15 min)

[A] = 4 [B]

=

t_{1 / 2}

=

t_{1 / 2}

=

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