Question

Two successive resonance frequencies in an open organ pipe are 1944 Hz and 2592 Hz. Find the length of the tube. The speed of sound in air is $324m{s}^{-1}$

• A. 1 m
• B. 10 cm
• C. 25 cm
• D. 50 cm

Answer 1

The correct option is C

25 cm

Generalizing $n\left(\frac{\lambda }{2}\right)=L$ $\lambda =\frac{v}{f}$

$f=\frac{nv}{2L}$

Next resonant frequency $=(n+1)\frac{v}{2L}$

Difference $=\left(\frac{v}{2L}\right)=2592-1944$

$L=25cm$