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Question

Two successive resonance frequencies in an open organ pipe are 1944 Hz and 2592 Hz. Find the length of the tube. The speed of sound in air is 324 ms1.
  1. 12.5 cm
  2. 25 cm
  3. None of these
  4. 50 cm


Solution

The correct option is B 25 cm
Δf=25921944=648 Hz
λ=vΔf=324648=12 m=50 cm
Also, length of the pipe is 
l=λ2=25 cm.

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