Question

Two supplementary angles differ by $34$. Find the angles?

Answer 1

Let the smaller angle be $x^o$
Since the two angles differ by ${34}^o$, the bigger angle $=x+{34}^o$
Since the sum of the supplementary angles is ${180}^o$
We have $x+(x+34)={180}^o$
$2x+34={180}^o$
$2x=180-34={146}^o$
$x=\frac{{146}^o}{2}={73}^o$
Therefore smaller angle $=x={73}^o$
Bigger angle $=x+34=73+34={107}^o$