Question

Two supplementary angles differ by ${44}^o$. Find the angles

Answer 1

Suppose that,

One angle is $x$

Then other angle is $x-{44}^o$

We know that,

$x+(x-{44}^o)={180}^o$ $\left(Suplementryangles\right)$

$2x-{44}^o={180}^o$

$2x={224}^o$

$x={112}^o$

Then, other angle is $x-{44}^o={112}^o-{44}^o={68}^o$

Hence, this is the answer.