Two supplementary angles differ by 48- Find the angles-

Let first angle = x Then second angle = x+48^∘ ∴ x + x+48^∘= 180^∘⇒ 2x+48^∘=180^∘ ⇒ 2x=180^∘ 48^∘=132^∘ x=132^∘/2=66^∘ ∴ First angle = 66^∘ and second angle ...

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Byju's Answer

Standard IX

Mathematics

Angles and Types of Angles

Two supplemen...

Question

Two supplementary angles differ by $48^{\circ}$ . Find the angles.

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Solution

Let first angle = x
Then second angle = $x + 48^{\circ}$
$∴ x + x + 48^{\circ} = 180^{\circ} \Rightarrow 2 x + 48^{\circ} = 180^{\circ} \Rightarrow 2 x = 180^{\circ} - 48^{\circ} = 132^{\circ} x = \frac{132^{\circ}}{2} = 66^{\circ}$
$∴$ First angle = $66^{\circ}$ and second angle = $x + 48^{\circ} = 66^{\circ} + 48^{\circ} = 114^{\circ}$
$∴$ Angles are $66^{\circ}, 114^{\circ}$

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Two supplementary angles differ by 48∘. Find the angles.

Let first angle = x Then second angle = x+48∘ ∴x+x+48∘=180∘⇒2x+48∘=180∘⇒2x=180∘−48∘=132∘x=132∘2=66∘ ∴ First angle = 66∘ and second angle =x+48∘=66∘+48∘=114∘ ∴ Angles are 66∘,114∘

Two supplementary angles differ by $48^{\circ}$ . Find the angles.