wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two swimmers swim in a stand still lake. First swimmer swims directly across the lake (30 m wide) with a velocity of 1.5 m/s, reaches the other end and runs a distance of 10 m in 10 seconds along the shore. What should be the velocity of the second swimmer so that he reaches the same point in the same time ?

A
(1.5^i1^j) m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(1.5^i+1^j) m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(1^i1.5^j) m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(13^i+^j) m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D (13^i+^j) m/s

Velocity of first swimmer, v1=1.5 m/s
Time taken to cover 10 m along the shore, tQR=10 s
For the second swimmer to reach the same point in same time, he should cover equal displacement in equal time.
Displacement of first swimmer, S=10^i+30^j
Time taken by first swimmer to reach the point R, t=tPQ+tQR
t=301.5+10=30 s
Therefore , velocity of second swimmer, v2=St=10^i+30^j30=(13^i+^j) m/s

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon