Question

Two symmetrical dice are thrown at a time. The probability that they show different faces is

• A. $\frac{5}{6}$
• B. $\frac{1}{36}$
• C. $\frac{25}{36}$
• D. $\frac{1}{18}$

Answer 1

Answer: (A)

$\frac{5}{6}$

Number of ways in which same face is shown $=6$
The probability that the same face is shown $=\frac{1}{36}=\frac{1}{6}$
The probability that different face is shown $=1-\frac{1}{6}=\frac{5}{6}$