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Question

Two tall buildings are 40 m apart. With what speed a ball must be thrown horizontally from a window 145 m above the ground in one building, so that it will enter a window 22.5 m above the ground in the other ?
(Take g=10 m/s2)

A
5 ms1
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B
8 ms1
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C
10 ms1
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D
16 ms1
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Solution

The correct option is B 8 ms1

Let the hprizontal velocity of ball be v
Vertical distance between the two windows =h=14522.5=122.5 m
Time taken by the ball to reach from one window to another =t=2hg
Therefore, horizontal distance covered
x=vxt
40=v2×122.510
40v×5
v8 ms1

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