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Derivation of Position-Velocity Relation by Graphical Method

two tall buil...

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two tall buildings face each other and are at a distance of 180 metres .with what velocity must a ball be thrown horizontally from a window 55 m above the ground in one building so that it enters a window 10.9m above the ground in second building?

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Q. Two tall buildings face each other and are at a distance of

180 m

from each other. With what velocity (in

m/s

) must a ball be thrown horizontally from a window

55 m

above the ground in one building, so that it enters a window

10.9 m

above the ground in the second building? (Take

g = 9.8 {m/s}^{2}

Q. Two tall buildings face each other and are at a distance of

180 m

from each other. With what velocity (in

m/s

) must a ball be thrown horizontally from a window

55 m

above the ground in one building, so that it enters a window

10.9 m

above the ground in the second building? (Take

g = 9.8 {m/s}^{2}

Q. Two tall buildings are

30 m

apart. The speed with which a ball must be thrown horizontally from a window

150 m

above the ground in one building so that it enters a window

27.5 m

from the ground in the other building is

Q. Two tall buildings are

80 m

apart. The velocity with which a ball should be thrown horizontally from a window

95 m

above the ground in one building so that it will enter a window

15 m

above the ground in the second building is : (

g = 10 m / s^{2}

)

Q. Two tall buildings are

40 m

apart. With what speed a ball must be thrown horizontally from a window

145 m

above the ground in one building, so that it will enter a window

22.5 m

above the ground in the other ?
(Take

g = 10 m / s^{2}

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Derivation of Position-Velocity Relation by Graphical Method

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