Two tangents are drawn from a point P to a circle touching the circle at A and B respectively . If PA = 6 cm and AB = 3 cm, then find the perimeter of triangle ABP .

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Solution

Given: PA = 6 cm and AB = 3 cm

By Theorem- Tangents drawn from an external point onto a circle are equal in length,

$∴$ PB = PA = 6 cm

$∴$ Perimeter of triangle ABP
= AB + PA + PB
= (3+6+6) cm = 15 cm

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Two tangents are drawn from a point P to a circle touching the circle at A and B respectively . If PA = 6 cm and AB = 3 cm, then find the perimeter of triangle ABP .

Given: PA = 6 cm and AB = 3 cm By Theorem- Tangents drawn from an external point onto a circle are equal in length, ∴ PB = PA = 6 cm ∴ Perimeter of triangle ABP = AB + PA + PB = (3+6+6) cm = 15 cm

Given: PA = 6 cm and AB = 3 cm

By Theorem- Tangents drawn from an external point onto a circle are equal in length,

$∴$ PB = PA = 6 cm

$∴$ Perimeter of triangle ABP
= AB + PA + PB
= (3+6+6) cm = 15 cm