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Question

Two tangents are drawn from a point to y2=4ax if these are normals to x2=4by then

A
a2>b2
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B
a2>4b2
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C
a2>8b2
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D
4a2>b2
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Solution

The correct option is D a2>8b2
Let the slopes of both lines from the external given point be m1 & m2
Equations of tangents to y2=4ax are
y=m1x+(am1) .....eqn(1)

& y=m2x+(am2)
Similarly equation of normal to x2=4by are
y=m1x+2b+(bm21) .....eqn(2)

y=m2x+2b+(bm22)
Thus, since lines written in both equations (1) & (2) are same
(am1)=2b+bm21

2bm21am1+b=0
Now, the discriminant is positive
i.e. D>0
(a)24×(2b)×(b)>0
a2>8b2
Hence, option (C) is correct.

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