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Byju's Answer
Standard XII
Mathematics
Tangent To a Parabola
Two tangents ...
Question
Two tangents are drawn from a point to
y
2
=
4
a
x
if these are normals to
x
2
=
4
b
y
then
A
a
2
>
b
2
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B
a
2
>
4
b
2
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C
a
2
>
8
b
2
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D
4
a
2
>
b
2
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Solution
The correct option is
D
a
2
>
8
b
2
Let the slopes of both lines from the external given point be
m
1
&
m
2
Equations of tangents to
y
2
=
4
a
x
are
⇒
y
=
m
1
x
+
(
a
m
1
)
.....
e
q
n
(
1
)
&
⇒
y
=
m
2
x
+
(
a
m
2
)
Similarly equation of normal to
x
2
=
4
b
y
are
⇒
y
=
m
1
x
+
2
b
+
(
b
m
2
1
)
.....
e
q
n
(
2
)
⇒
y
=
m
2
x
+
2
b
+
(
b
m
2
2
)
Thus, since lines written in both equations (1) & (2) are same
(
a
m
1
)
=
2
b
+
b
m
2
1
⇒
2
b
m
2
1
−
a
m
1
+
b
=
0
Now, the discriminant is positive
i.e.
D
>
0
⇒
(
−
a
)
2
−
4
×
(
2
b
)
×
(
b
)
>
0
⇒
a
2
>
8
b
2
Hence, option (C) is correct.
Suggest Corrections
0
Similar questions
Q.
If the tangents drawn from a point to the parabola
y
2
=
4
a
x
are also normals to the parabola
x
2
=
4
b
y
, then
Q.
If
a
2
>
8
b
2
,
prove that a point can be found such that the two tangents from it to the parabola
y
2
=
4
a
x
are normals to the parabola
x
2
=
4
b
y
.
Q.
If tangent to
x
2
a
2
+
y
2
b
2
=
1
meets the axes at
A
and
B
,
then the locus of mid point of
A
B
is
Q.
p
(
θ
)
,
D
(
θ
+
π
2
)
are two points on the Ellipse
x
2
a
2
+
y
2
b
2
=
1
Then the locus of point of intersection of the two tangents at P and D to the ellipse is
Q.
Assertion :Perpendicular tangents can be drawn to hyperbola
x
2
a
2
−
y
2
b
2
=
1
only if
e
>
√
2
. Reason: Locus of point of intersection of perpendicular tangents to
x
2
a
2
−
y
2
b
2
=
1
is
x
2
+
y
2
=
a
2
−
b
2
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