Relation between Inradius and Perimeter of Triangle
Two tangents ...
Question
Two tangents are drawn to a circle from an external point A, touching the circle at the points P and Q. A third tangent intersects segment AP at B and segment AQ at C and touches the circle at R. If AQ=10 units, then the perimeter of ΔABC is
A
22.0
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B
20.5
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C
20.0
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D
40.0
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Solution
The correct option is A20.0 Since the tangents to a circle from an external point are equal in length AP=AQ=10units and $BP = BRCQ=CR$ Adding these, we get, BP+CQ=BR+CR=BC Adding AB and AC to both sides, we get BP+CQ+AB+AC=BC+AB+AC ⇒(BP+AB)+(CQ+AC)=AB+BC+AC ⇒AP+AQ=Perimeterof\Delta ABC$ ⇒(10+10) units = Perimeter of ΔABC ∴ Perimeter of ΔABC=20 units,