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Question

Two tangents are drawn to a circle from an external point A, touching the circle at the points P and Q. A third tangent intersects segment AP at B and segment AQ at C and touches the circle at R. If AQ=10 units, then the perimeter of ΔABC is

A
22.0
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B
20.5
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C
20.0
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D
40.0
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Solution

The correct option is A 20.0
Since the tangents to a circle from an external point are equal in length
AP=AQ=10units
and $BP = BRCQ=CR$
Adding these, we get,
BP+CQ=BR+CR=BC
Adding AB and AC to both sides, we get
BP+CQ+AB+AC=BC+AB+AC
(BP+AB)+(CQ+AC)=AB+BC+AC
AP+AQ=Perimeterof\Delta ABC$
(10+10) units = Perimeter of ΔABC
Perimeter of ΔABC=20 units,
400176_375372_ans.jpg

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