The correct option is B y2=8(x−1)
The end points of the latus rectum are (1,±2)
equation of the tangents drown to the end points are
y=±(x+1)⋯(1)
By the symmetry, it can be concluded as axis of the required parabola will be same as the axis of the given parabola.
Now let the equation of the required parabola is
y2=4a(x−1)⋯(2)
equating (1) and (2)
x2+1+2x=4a(x−1)
For tangency D=0
⇒(2−4a)2=4(4a+1)⇒4+16a2−16a=16a+4⇒a=0,2
a=0 is not valid
So equation will be y2=8(x−1)