We are given two tangents PA and PB drawn to a circle with centre O from external point P
We are to prove that quadrilateral AOBP is cyclic
We know that tangent at a point to a circle is perpendicular to the radius through that point.
Therefore from figure
That is
In quadrilateral AOBP,
[Sum of angles of a quadrilateral = 360°]
We know that the sum of opposite angles of cyclic quadrilateral = 180°
Therefore from (1) and (2)
Quadrilateral AOBP is a cyclic quadrilateral.