Two tangents PA and PB are drawn to the circle with centre O, such that ∠APB =120∘what is the relation between OP and AP?
OP = 1/2 AP
AP = 2 /3 OP
OP = 2 AP
OP = AP
∠APB = 120∘
∠APO = ∠OPB=60∘
cos 60∘= APOP 12 = APOP
OP = 2AP
Two tangents PA and PB are drawn from an external point P to the circle with centre O, such that ∠APB =120∘what is the relation between OP and AP?