Two taps can fill a cistern in 10 hours in 8 hours respectively a third tapthat can empty it in 15 hours how long will it take to fill the empty cistern ifall of them are opened together?

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Solution

a+b's 1hr work=1/10+1/8
third tap empty =1/15 of tank
all taps opend together 1/10+1/8-1/15 of tank==19/120
1hr=19/120 of tank
120/9 hrs=complet tank=6 6/19

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Two taps can fill a cistern in 10 hours in 8 hours respectively a third tapthat can empty it in 15 hours how long will it take to fill the empty cistern ifall of them are opened together?

a+b's 1hr work=1/10+1/8 third tap empty =1/15 of tank all taps opend together 1/10+1/8-1/15 of tank==19/120 1hr=19/120 of tank 120/9 hrs=complet tank=6 6/19

a+b's 1hr work=1/10+1/8
third tap empty =1/15 of tank
all taps opend together 1/10+1/8-1/15 of tank==19/120
1hr=19/120 of tank
120/9 hrs=complet tank=6 6/19