Two taps can fill a tub in 5 minutes and 7 minutes respectively A pipe can empty it in 3 minutes If all the three are kept open simultaneously when will the tub be full?

60 minutes

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85 minutes

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90 minutes

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105 minutes

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Solution

The correct option is D 105 minutes
Given Two taps can fill a tub in 5 minutes and 7 minutes respectively A pipe can empty it in 3 minutes
Then net part fill in one hours = $\frac{1}{5} + \frac{1}{7} - \frac{1}{3} = \frac{21 + 15 + - 35}{105} = \frac{1}{105}$
Then total tank fill in 105 minites

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Two taps can fill a tub in 5 minutes and 7 minutes respectively A pipe can empty it in 3 minutes If all the three are kept open simultaneously when will the tub be full?

The correct option is D 105 minutesGiven Two taps can fill a tub in 5 minutes and 7 minutes respectively A pipe can empty it in 3 minutesThen net part fill in one hours =15+17−13=21+15+−35105=1105Then total tank fill in 105 minites

The correct option is D 105 minutes
Given Two taps can fill a tub in 5 minutes and 7 minutes respectively A pipe can empty it in 3 minutes
Then net part fill in one hours = $\frac{1}{5} + \frac{1}{7} - \frac{1}{3} = \frac{21 + 15 + - 35}{105} = \frac{1}{105}$
Then total tank fill in 105 minites