Question

Two test tubes containing a nitrate and a bromide are treated separately with $H_{2}S{O}_4$; brown fumes evolved are passed in water. The water will be colored by vapors evolved from the test tube containing :

• A. Nitrate
• B. Bromide
• C. Both (a) and (b)
• D. None of these

Answer 1

The correct option is B Bromide

The water will be colored by vapors evolved from the test tube containing bromide.

$B{r}_2+H_{2}O⟶Browncolor$

$N{O}_2+H_{2}O⟶Colorless$.

$B{r}_2$ impart a brown color to the aqueous solution while $N{O}_2$ does not.

So, the correct option is $B$