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Question

Two thin dielectric slabs of dielectric constants K1 and K2(K1<K2) are inserted between the plates of a parallel plate capacitor, as shown in the figure below. The variation of electric field E between the plates with distance d as measured from plate P is correctly shown by -

A
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C
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Solution

The correct option is C
When a dielectric material is inserted in between the plates of capacitor, the dielectric becomes electrically polarized. The polarization charges induced on the two faces of the slab produce their own electric field Eo​​ , which opposes the external field Eo​​. Hence, the resultant field E within the dielectric is smaller than Eo​ but is in the same direction as Eo​​ and is given by E=EoK​.
The electric field inside the dielectric will be less than the electric field outside the dielectrics. The electric field inside the dielectrics cannot not be zero.
As K2>K1, the drop in electric field for K2 dielectric must be more than K1
Hence, graph (c) is correct.

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