Two thin lenses of focal; lengths $f_{1}$ and $f_{2}$ are in contact and coaxial. The combination is equivalent to a single lens of power

f_{1} + f_{2}

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\frac{f_{1} f_{2}}{f_{1} + f_{2}}

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\frac{1}{2} (f_{1} + f_{2})

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\frac{f_{1} + f_{2}}{f_{1} f_{2}}

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Solution

The correct option is D $\frac{f_{1} + f_{2}}{f_{1} f_{2}}$
As we know,
$P = \frac{1}{F} = \frac{f_{1} + f_{2}}{f_{1} f_{2}}$

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Similar questions

Two thin lenses of focal lengths $f_{1}$ and $f_{2}$ are placed in contact with each other. The focal length of the combination will be given by:

If two thin lenses of focal length f₁ and f₂ are held in contact then the focal length of the combination will be

f_{1}

f_{2}

f_{1} a n d f_{2}

d < f_{1}, d < f_{2}

Δ

f_{1}

f_{2}

\frac{1}{f} = \frac{1}{f_{1}} + \frac{1}{f_{2}}

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