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Question

Two thin rings each having a radius R are placed at distance d apart with their axes coinciding. The charges on the two rings are +q,q. The potential difference between the rings is:


A
qR4πε0d2
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B
q2πε0(1R1R2+d2)
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C
q4πε0(1R1R2+d2)
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D
0
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Solution

The correct option is A q2πε0(1R1R2+d2)
Potential due to a ring of charge q at any point d distance away from the center of the ring on its axis is given by kq/R2+d2 where R is the radius of the ring.
From the diagram:
the potential on the center of ring 1=kq(1/R1/R2+d2)
and the potential on the center of ring 2=kq(1/R1/R2+d2)
Difference in the potentials is thus,
=2kq(1/R1/R2+d2)
92333_10588_ans.png

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