Two towers of the same height stand on opposite sides of a road 100 m wide. At a point on the road between the towers, the elevations of the towers are 30∘ and 45∘ Find the height of the towers and the position of the point from one of the towers:
36.6 m and 63.4 m
Let the height of each building be 'h' m and let the point be at a distance of 'x' m from the one having an elevation of 30 degrees.
tan 30 = hx => x = 1.732×h ---(1)
tan 45 = h(100−x) => 100 - x = h
Putting the value of x from eqn (1), we get
h = 36.6 m
x = 63. 4 m