Two traffic sign boards are placed beside a highway. They look like two isosceles $triangles. Find the ratio of \frac{A B}{X Y} .$

\frac{3}{5}

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\frac{5}{3}

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\frac{6}{5}

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\frac{5}{6}

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Solution

The correct option is A $\frac{3}{5}$

Given are two isosceles triangles.
So, AB = AC = 150 in.
And, XY = XZ = 250 in.

$∴ The ratio of AB and XY = \frac{A B}{X Y}$

$= \frac{150}{250}$

$= \frac{3}{5}$

So, we can write:
$\frac{A B}{X Y} = \frac{B C}{Y Z} = \frac{A C}{X Z} = \frac{3}{5}$

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Two traffic sign boards are placed beside a highway. They look like two isosceles triangles. Find the ratio of ABXY.

The correct option is A 35 Given are two isosceles triangles. So, AB = AC = 150 in. And, XY = XZ = 250 in. ∴ The ratio of AB and XY=ABXY =150250 =35 So, we can write: ABXY=BCYZ=ACXZ=35

Two traffic sign boards are placed beside a highway. They look like two isosceles $triangles. Find the ratio of \frac{A B}{X Y} .$

The correct option is A $\frac{3}{5}$

Given are two isosceles triangles.
So, AB = AC = 150 in.
And, XY = XZ = 250 in.

$∴ The ratio of AB and XY = \frac{A B}{X Y}$

$= \frac{150}{250}$

$= \frac{3}{5}$

So, we can write:
$\frac{A B}{X Y} = \frac{B C}{Y Z} = \frac{A C}{X Z} = \frac{3}{5}$