Two train are moving in opposite direction at speed of 60km/hour and 90km/hour, their length are 1.10 km and 0.9 km, respectively. The time taken by the slower train to cross the faster train in seconds is

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Solution

The correct option is D 48
Distance $= 1.1 + 0.9 = 2 k m$
and speed $= (60 + 90) = 150$
time taken $= \frac{2 \times 1000}{150 \times \frac{5}{18}} = 48 s e c$

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Two train are moving in opposite direction at speed of 60km/hour and 90km/hour, their length are 1.10 km and 0.9 km, respectively. The time taken by the slower train to cross the faster train in seconds is

The correct option is D 48Distance =1.1+0.9=2km and speed =(60+90)=150time taken =2×1000150×518=48sec

The correct option is D 48
Distance $= 1.1 + 0.9 = 2 k m$
and speed $= (60 + 90) = 150$
time taken $= \frac{2 \times 1000}{150 \times \frac{5}{18}} = 48 s e c$