Two traingles are given as $△ A B C$ and $△ X Y Z$ where, $A B = Z X$ , $B C = X Y$ and $A C = Z Y$ . Then which of the following is correct ?

△ A B C ≅ △ X Y Z (S S S P r o p e r t y)

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△ A B C ≅ △ Z X Y (S S S p r o p e r t y)

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△ A B C ≅ △ Y Z X (S S S P r o p e r t y)

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All are correct.

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Solution

The correct option is B $△ A B C ≅ △ Z X Y (S S S p r o p e r t y)$
In the above question, we know that $A B = Z X$ , $B C = X Y$ and $A C = Z Y$ .

So, we can say that vertex $A$ is congruent with $Z$ , $B$ with $X$ and $C$ with $Y$ .

Also, all the three corresponding sides of one triangle are equal to those of the other triangle.
So,
$△ A B C ≅ △ Z X Y (S S S p r o p e r t y)$
Hence, option $(b)$ correct.

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