Two trains 140m and 160m long run at the speed of 60km/hr and 40km/hr respectively in opposite direction on parallel tracks. The time (in seconds) which they take to cross each other is

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9.6

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10.8

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Solution

The correct option is D 10.8
Relative speed $= (60 + 40) k m / h r = (100 \times \frac{5}{18}) m / s e c = (\frac{250}{9}) m / s e c .$

Distance covered in crossing each other $= (140 + 160) m = 300 m$

Required time $= \frac{D i s t a n c e}{S p e e d}$ $= \frac{300}{(\frac{250}{9})}$ $= (300 \times \frac{9}{250}) s e c = \frac{54}{5} s e c = 10.8 s e c .$

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Two trains 140m and 160m long run at the speed of 60km/hr and 40km/hr respectively in opposite direction on parallel tracks. The time (in seconds) which they take to cross each other is

The correct option is D 10.8Relative speed =(60+40)km/hr=(100×518)m/sec=(2509)m/sec.Distance covered in crossing each other =(140+160)m=300mRequired time =DistanceSpeed=300(2509)=(300×9250)sec=545sec=10.8sec.