wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two trains, A and B, each 50 m long, are approaching a meeting point travelling with velocities 10 m/s and 15 m/s respectively. The tracks of the two trains are perpendicular to each other and both trains are 500 meters away from the meeting point. How far will be the train A from meeting point when train B crosses the meeting point?

A
135 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
133.3 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
130.0 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
123.3 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 133.3 m
Since train B is traveling with higher speed than train A, B will reach first.
For the last coach of train B to reach meeting point, total distance train B has to travel is 550 m with velocity 15 m/s.
Time taken to cross 550 m is
t=sv=55015=36.67 s
In that period train, A moves a distance of
s=10×36.67=366.7 m.
Distance from the meeting point =500366.7=133.3 m

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion in 2D
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon