Question

Two trains are running in the same directions at the speed of $60$ km/hr and $96$ km/hr. If the faster train passes a man in the slower train in $20$ seconds, then the length of the faster train is

• A. $100$ m
• B. $125$ m
• C. $150$ m
• D. $200$ m

Answer 1

The correct option is D $200$ m

Relative speed = ($96-60$) km/hr = $36$ km/hr $=(36\times \frac{5}{18})$ m/s = $10$ m/sec
As we know D = s x t $\therefore$ Length of faster train = $10\times 20$ = $200$ m