Two trains are traveling in the same direction at 50 km/h and 30 km/h respectively. The faster train crosses a man in the slower train in 18 seconds. Find the length of the faster train.

0.1 km

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1 km

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1.5 km

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1.4 km

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Solution

The correct option is A 0.1 km
$t = \frac{L_{T} + L_{o}}{S_{T} + S_{o}} 50 - 30 = 20 k m / h r = 50 / 9 m / s n o w 18 = \frac{L_{T}}{50 / 9} \Rightarrow L_{T} = 100 m$

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