Two trains each of length $100 m$ moving parallel towards each other at speed $72 k m / h$ and $36 k m / h$ respectively. In how much time will they cross each other?

4.5 S

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6.67 s

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3.5 s

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7.25 s

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Solution

The correct option is B $6.67 s$
Total lengh to be covered $(l) = 200 m$
Total relative speed $(v) = ({\to v}_{1} - {\to v}_{2}) = 72 - (- 36) = 108 k m / h = 108 \times \frac{5}{18} = 30 m / s$
So, Time taken to cross each other $= \frac{l}{v} = \frac{200}{30} = 6.67 s$
Therefore, B is correct option.

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Two trains each of length 100 m moving parallel towards each other at speed 72 km/h and 36 km/h respectively. In how much time will they cross each other?

The correct option is B 6.67 sTotal lengh to be covered (l)=200mTotal relative speed (v)=(→v1−→v2)=72−(−36)=108km/h=108×518=30m/sSo, Time taken to cross each other =lv=20030=6.67sTherefore, B is correct option.

Two trains each of length $100 m$ moving parallel towards each other at speed $72 k m / h$ and $36 k m / h$ respectively. In how much time will they cross each other?