Two trains having length of 280 m and 320 m long run at the speed of 120 kmph and 80 kmph respectively in opposite directions (on parallel tracks). What is the time which they will take to cross each other?

8.8 secs

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10.8 secs

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12.8 secs

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11.2 secs

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None of these

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Solution

The correct option is B
10.8 secs

Distance = 280 + 320 = 600 m

Relative speed = 120 + 80 = 200 kmph = $\frac{200 \times 5}{18}$ m/s

Time = distance/speed = $\frac{600}{\frac{500}{9}}$ = $\frac{600 \times 9}{500}$ = $\frac{54}{5}$ = 10.8 secs

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Two trains having length of 280 m and 320 m long run at the speed of 120 kmph and 80 kmph respectively in opposite directions (on parallel tracks). What is the time which they will take to cross each other?

The correct option is B 10.8 secs Distance = 280 + 320 = 600 m Relative speed = 120 + 80 = 200 kmph = 200×518 m/s Time = distance/speed = 6005009 = 600×9500 = 545 = 10.8 secs

The correct option is B
10.8 secs

Distance = 280 + 320 = 600 m

Relative speed = 120 + 80 = 200 kmph = $\frac{200 \times 5}{18}$ m/s

Time = distance/speed = $\frac{600}{\frac{500}{9}}$ = $\frac{600 \times 9}{500}$ = $\frac{54}{5}$ = 10.8 secs