Two trains of equal length take $10$ seconds and $15$ seconds respectively to cross a telegraph post. If the length of each train be $120$ meters. In what time (in seconds) will they cross each other in opposite directions?

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Solution

The correct option is D $12$
Speed of first train $= \frac{120}{10} = 12$ m/sec
Speed of second train $= \frac{120}{15} = 8$ m/sec
Relative speed $= 12 + 8 = 20$ m/sec
Therefore, required time $= \frac{120 + 120}{20} = 12$ sec.

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Two trains of equal length take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 meters. In what time (in seconds) will they cross each other in opposite directions?

The correct option is D 12Speed of first train =12010=12 m/secSpeed of second train =12015=8 m/secRelative speed =12+8=20 m/secTherefore, required time =120+12020=12 sec.

Two trains of equal length take $10$ seconds and $15$ seconds respectively to cross a telegraph post. If the length of each train be $120$ meters. In what time (in seconds) will they cross each other in opposite directions?

The correct option is D $12$
Speed of first train $= \frac{120}{10} = 12$ m/sec
Speed of second train $= \frac{120}{15} = 8$ m/sec
Relative speed $= 12 + 8 = 20$ m/sec
Therefore, required time $= \frac{120 + 120}{20} = 12$ sec.