Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is
A
1:2
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B
3:2
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C
3:4
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D
4:3
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Solution
The correct option is B3:2 Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, the length of first train =27x m
and the length of second train =17y m.
Now, 27x+17yx+y=23 ⇒27x+17y=23x+23y ⇒4x=6y ∴xy=32