Question

Two trains start from stations $A$ and $B$ and travel towards each other at $50$ km/hr and $60$ km/hr respectively. At the time of their meeting the second train has travelled $120$ km more than the first. The distance between $A$ and $B$ is

• A. $990$ km
• B. $1200$ km
• C. $1320$ km
• D. $1440$ km

Answer 1

The correct option is C $1320$ km

Let the two trains meet after x hours. Then, $60x-50x=120\Rightarrow 10x=120\Rightarrow x=12hrs$
Distance AB $=$ (Dist. covered by slower train) + (Dist. covered by faster train)
$=\left[\right(50\times 12)+(60\times 12\left)\right]km$
$=600km+720km=1320km$