Two travelers start walking from the same point at an angle of 150 $^{o}$ with each other at the rate of 4 kmph and 3 kmph. Find the distance between them after 2 hours.

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28-48√3

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none of these

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Solution

The correct option is C

let OA and OB be the paths traveled by the two travelers in 2 hours.

In right angled triangle OCB, BC= $\frac{6}{2}$ =3 KM and OC= 3√3 km

In right angled triangle ACB, AB2= AC2 + BC2 = (8+3√3)²+3²= 100+48√3

$2 \sqrt{25 + 12 \sqrt{3}}$

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Two travelers start walking from the same point at an angle of 150o with each other at the rate of 4 kmph and 3 kmph. Find the distance between them after 2 hours.

The correct option is C let OA and OB be the paths traveled by the two travelers in 2 hours. In right angled triangle OCB, BC= 62 =3 KM and OC= 3√3 km In right angled triangle ACB, AB2= AC2 + BC2 = (8+3√3)2+32= 100+48√3 2√25+12√3

Two travelers start walking from the same point at an angle of 150 $^{o}$ with each other at the rate of 4 kmph and 3 kmph. Find the distance between them after 2 hours.

The correct option is C

let OA and OB be the paths traveled by the two travelers in 2 hours.

In right angled triangle OCB, BC= $\frac{6}{2}$ =3 KM and OC= 3√3 km

In right angled triangle ACB, AB2= AC2 + BC2 = (8+3√3)²+3²= 100+48√3

$2 \sqrt{25 + 12 \sqrt{3}}$