Question

Two trees 7 m and 4 m high stand upright on a ground. If their bases (roots) are 4 m apart, then the distance between their tops is

Answer 1

Consider PQ is the tree of height 7m and RS is the tree of height 4 m.
So, consider the triangles QRE, from the Pythagoras theorem,
$Q{R}^2=Q{E}^2+E{R}^2$
$Q{R}^2=32+42$
$Q{R}^2=9+16$
$Q{R}^2=25$
$QR=\sqrt{25}$
QR = 5
Therefore, the distance between the top of the two trees is 5m.