Question

Two triangles ABC and PQR are such that AB = 3 cm, AC = 6 cm, ∠A = 70⁰ PR = 9 cm, ∠P = 70⁰ and PQ = 4.5 cm. Show that
△ABC ∼ △PQR and state similarity theorem.

Answer 1

Now, In △ABC and △PQR
∠A = ∠P = 70⁰ (Given)
$\frac{\mathrm{AB}}{\mathrm{PQ}}=\frac{\mathrm{AC}}{\mathrm{PR}}\left[\because \frac{3}{4.5}=\frac{6}{9}\Rightarrow \frac{1}{1.5}=\frac{1}{1.5}\right]$
By SAS similarity criterion, △ABC ∼ △PQR