Two triangles DEF and GHK are such that ∠D=48o and ∠H=57o. If ΔDEF∼ΔGHK then find the measure of ∠F.
In two triangles are similar then the corresponding angles of the two triangles are equal.
Here, ΔDEF∼ΔGHK
Therefore, ∠E=∠H=57o
Now, in ΔDEF
∠D+∠E+∠F=180o (Angle sum property of triangle)
⇒ ∠F=180o–48o–57o=75o
∠F=75o