Two tuning fork when sounded together,produce 4 beats /s. One of the fork is in unison with 30 cm length of sonometer wire and the other with 25 cm length of the same wire. The frequency of the two tunning forks are

87 Hz : 84 Hz

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20 Hz : 24 Hz

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81 Hz : 78 Hz

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84 Hz : 81 Hz

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Solution

The correct option is B 20 Hz : 24 Hz
$(f_{1} / f_{2}) = (l_{2} / l_{1}) = (25 / 30) = (5 / 6)$
$f_{2} - f_{1} = 4$
$∴ (6 / 5) f_{1} - f_{1} = 4$
$(f_{1} / 5) = 4$
$f_{1} = 20 H Z$
$f_{2} = 24 H Z$
Hence,
option $(B)$ is correct answer.

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Two tuning fork when sounded together,produce 4 beats /s. One of the fork is in unison with 30 cm length of sonometer wire and the other with 25 cm length of the same wire. The frequency of the two tunning forks are

The correct option is B 20 Hz : 24 Hz(f1/f2)=(l2/l1)=(25/30)=(5/6)f2−f1=4∴(6/5)f1−f1=4(f1/5)=4f1=20HZf2=24HZHence,option (B) is correct answer.

The correct option is B 20 Hz : 24 Hz
$(f_{1} / f_{2}) = (l_{2} / l_{1}) = (25 / 30) = (5 / 6)$
$f_{2} - f_{1} = 4$
$∴ (6 / 5) f_{1} - f_{1} = 4$
$(f_{1} / 5) = 4$
$f_{1} = 20 H Z$
$f_{2} = 24 H Z$
Hence,
option $(B)$ is correct answer.