Two tuning forks, A and B, produce notes of frequencies 258Hz and 262Hz. An unknown note sounded with A produces certain beats. When the same note is sounded with B, the beat frequency gets doubled. The unknown frequency is
A
250Hz
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B
252Hz
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C
254Hz
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D
256Hz
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Solution
The correct option is A254Hz Here, υA=258Hz,υB=262Hz Let the frequency of unknown turning fork be υ. It produces υb beats with A and 2υb with B. Therefore, υA−υ=υb ......(i) and υB−υ=2υb ......(ii) Subtract (i) from (ii), we get υB−υA=υb Substituting the giving values, we get 262−258=υb υb=4Hz From (i), υ=υA−υb=(258−4)Hz=254Hz